b^2-11b+28=-2

Solution for b^2-11b+28=-2 equation:

Simplifying
b2 + -11b + 28 = -2

Reorder the terms:
28 + -11b + b2 = -2

Solving
28 + -11b + b2 = -2

Solving for variable 'b'.

Reorder the terms:
28 + 2 + -11b + b2 = -2 + 2

Combine like terms: 28 + 2 = 30
30 + -11b + b2 = -2 + 2

Combine like terms: -2 + 2 = 0
30 + -11b + b2 = 0

Factor a trinomial.
(5 + -1b)(6 + -1b) = 0

Subproblem 1
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Subproblem 2
Set the factor '(6 + -1b)' equal to zero and attempt to solve:

Simplifying
6 + -1b = 0

Solving
6 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1b = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1b = 0 + -6
-1b = 0 + -6

Combine like terms: 0 + -6 = -6
-1b = -6

Divide each side by '-1'.
b = 6

Simplifying
b = 6
Solution
b = {5, 6}